I can't make my code pass this test:
it "translates two words" do
s = translate("eat pie")
s.should == "eatay iepay"
end
I don't see the flaw in my logic, though it may be very brute force and there may be a simpler way of passing the test:
def translate(string)
string_array = string.split
string_length = string_array.size
i=0
while i < string_length
word = string_array[i]
if word[0] == ("a" || "e" || "i" || "o" || "u")
word = word + "ay"
string_array[i] = word
elsif word[0] != ( "a" || "e" || "i" || "o" || "u" ) && word[1] != ( "a" || "e" || "i" || "o" || "u" )
word_length = word.length-1
word = word[2..word_length]+word[0]+word[1]+"ay"
string_array[i] = word
elsif word[0] != ( "a" || "e" || "i" || "o" || "u" )
word_length = word.length-1
word = word[1..word_length]+word[0]+"ay"
string_array[i] = word
end
i += 1
end
return string_array.join(" ")
end
Here's the test failure message:
Failures:
1) #translate translates two words
Failure/Error: s.should == "eatay iepay"
expected: "eatay iepay"
got: "ateay epiay" (using ==)
# ./04_pig_latin/pig_latin_spec.rb:41:in `block (2 levels) in <top (required)>'
The additional code checking other conditions are for other tests that I already passed. Basically, now I'm checking a string with two words.
Please let me know how I can make the code pass the test. Thank you in advance!
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