python code for the even digits problem in 2018 google kickstart

I get the result as "Wrong answer" when I submit my code. But I get the wright answers while testing myself.

My code:

def check_even(digits):
temp=[]
for i in range(0,len(digits)):
    if digits[i] & 1:
        temp.append(1)
    else:
        temp.append(0)
return temp    

T=int(input())

num=[]
digits=[]
for i in range(0,T):
    num.append(input())
    digits.append(list(map(int,str(num[i]))))


for element in range(0,len(digits)):
    temp=check_even(digits[element])
    td=int(num[element])
    if 1 in temp:


    #add
    for i in range(1,len(temp)+1):
        if temp[-i]==1:
            td+=pow(10,i-1)-td%pow(10,i-1)
            temp=check_even(list(map(int,str(td))))
    add=td-int(num[element])


    #sub
    temp=check_even(digits[element])
    td=int(num[element])
    pos = temp.index(1)
    count=len(str(td))-(pos+1)
    td-=td%pow(10,count)
    sub_num=('1'*(count-1))+'2'
    td-=int(sub_num)
    sub=int(num[element])-td


    if add<sub:
        print("Case #{}: {}".format(element+1,add))
    else:
        print("Case #{}: {}".format(element+1,sub))


    else:
        print("Case #{}: {}".format(element+1,0))

This code is the solution for google kickstart 2018 "Even digits" problem

Problem statement: Google kickstart 2018 Round A